
	<span class="Z3988" title="ctx_ver=Z39.88-2004&amp;rft_val_fmt=info%3Aofi%2Ffmt%3Akev%3Amtx%3Adc&amp;rfr_id=info%3Asid%2Focoins.info%3Agenerator&amp;rft.title=LEDs+%26%23038%3B+resistors&amp;rft.aulast=Stavrakis&amp;rft.aufirst=Modestos&amp;rft.subject=electronics&amp;rft.subject=technology&amp;rft.source=%CE%BC%CE%BF.&amp;rft.date=2011-04-18&amp;rft.type=blogPost&amp;rft.format=text&amp;rft.identifier=https://xylem.aegean.gr/~modestos/mo.blog/leds-resistors/&amp;rft.language=English"></span>

	<span class="Z3988" title="ctx_ver=Z39.88-2004&amp;rft_val_fmt=info%3Aofi%2Ffmt%3Akev%3Amtx%3Adc&amp;rfr_id=info%3Asid%2Focoins.info%3Agenerator&amp;rft.title=LEDs+%26%23038%3B+resistors&amp;rft.aulast=Stavrakis&amp;rft.aufirst=Modestos&amp;rft.subject=electronics&amp;rft.subject=technology&amp;rft.source=%CE%BC%CE%BF.&amp;rft.date=2011-04-18&amp;rft.type=blogPost&amp;rft.format=text&amp;rft.identifier=https://xylem.aegean.gr/~modestos/mo.blog/leds-resistors/&amp;rft.language=English"></span>
{"id":4071,"date":"2011-04-18T14:30:11","date_gmt":"2011-04-18T12:30:11","guid":{"rendered":"http:\/\/xylem.aegean.gr\/~modestos\/mo.blog\/?p=4071"},"modified":"2016-01-12T21:09:35","modified_gmt":"2016-01-12T19:09:35","slug":"leds-resistors","status":"publish","type":"post","link":"https:\/\/xylem.aegean.gr\/~modestos\/mo.blog\/leds-resistors\/","title":{"rendered":"LEDs &#038; resistors"},"content":{"rendered":"<p>&nbsp;<\/p>\n<p>To calculate the resistance when powering a LED use this:<\/p>\n<p style=\"text-align: center;\"><span style=\"font-size: medium;\"><strong>R=(Vpow-Vled)\/I<\/strong><\/span><\/p>\n<ul>\n<li><strong>R: <\/strong>is the needed resistance<\/li>\n<li><strong>Vpow: <\/strong>is the voltage of our source or power supply (e.g. battery)<\/li>\n<li><strong>Vled: <\/strong>voltage of the LED<\/li>\n<li><strong>I<\/strong>: the maximum of current that goes through our LED.<\/li>\n<\/ul>\n<p>for a 2V (diode forward voltage) LED we need 20mA =0.02A (diode forward current)<\/p>\n<p>So, for instance, if we have a 12V battery then: R=(12-2)\/0,02= 10\/0.02=500 Ohm<\/p>\n<p>Another example is the use of multiple LEDs in an array. So, for an array of 4 LEDs with diode forward voltage 2V, diode forward current (0.02mA) and a Vpow of 12V we need:<\/p>\n<div>\n<p>4 x 1 array uses 4 LEDs exactly<\/p>\n<table cellspacing=\"0\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td>+12V<\/td>\n<td>\n<table cellspacing=\"0\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/led.linear1.org\/i\/wiz\/wizc-lterm4.png?resize=35%2C35\" alt=\"+\" width=\"35\" height=\"35\" \/><\/td>\n<td><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/led.linear1.org\/i\/wiz\/wizc-d.png?resize=35%2C35\" alt=\"-|&gt;|-\" width=\"35\" height=\"35\" \/><\/td>\n<td><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/led.linear1.org\/i\/wiz\/wizc-d.png?resize=35%2C35\" alt=\"-|&gt;|-\" width=\"35\" height=\"35\" \/><\/td>\n<td><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/led.linear1.org\/i\/wiz\/wizc-d.png?resize=35%2C35\" alt=\"-|&gt;|-\" width=\"35\" height=\"35\" \/><\/td>\n<td><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/led.linear1.org\/i\/wiz\/wizc-d.png?resize=35%2C35\" alt=\"-|&gt;|-\" width=\"35\" height=\"35\" \/><\/td>\n<td><img data-recalc-dims=\"1\" decoding=\"async\" title=\"R = 220000 ohms\" src=\"https:\/\/i0.wp.com\/led.linear1.org\/i\/wiz\/wizc-r.png?resize=35%2C35\" alt=\"-\/\/\/-\" width=\"35\" height=\"35\" \/><\/td>\n<td><img data-recalc-dims=\"1\" decoding=\"async\" src=\"https:\/\/i0.wp.com\/led.linear1.org\/i\/wiz\/wizc-rterm4.png?resize=35%2C35\" alt=\"+\" width=\"35\" height=\"35\" \/><\/td>\n<td>R\u00a0=\u00a0220000\u00a0ohms<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<ul>\n<li>each 220000 ohm resistor dissipates 0.088 mW<\/li>\n<li>the wizard says the color code for 220000 is red red yellow<\/li>\n<li>the wizard thinks 1\/4W resistors are fine for your application<\/li>\n<li>together, all resistors dissipate 0.088 mW<\/li>\n<li>together, the diodes dissipate 0.16 mW<\/li>\n<li>total power dissipated by the array is 0.248 mW<\/li>\n<li>the array draws current of 0.02 mA from the source.<\/li>\n<\/ul>\n<p>Here is a calculator to automatically find your needed resistance [<a href=\"http:\/\/led.linear1.org\/1led.wiz\">&gt;&gt;<\/a>].<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>&nbsp; To calculate the resistance when powering a LED use this: R=(Vpow-Vled)\/I R: is the needed resistance Vpow: is the voltage of our source or power supply (e.g. battery) Vled: voltage of the LED I: the maximum of current that goes through our LED. for a 2V (diode forward voltage) LED we need 20mA =0.02A (diode forward current) So, for instance, if we have a 12V battery then: R=(12-2)\/0,02= 10\/0.02=500 Ohm Another example is the use of multiple LEDs in an array. So, for an array of 4 LEDs with diode forward voltage 2V, diode forward current (0.02mA) and a Vpow of 12V we need: 4 x 1 array uses 4 LEDs exactly +12V R\u00a0=\u00a0220000\u00a0ohms each 220000 ohm resistor dissipates 0.088 mW the wizard says the color code for 220000 is red red yellow the wizard thinks 1\/4W resistors are fine for your application together, all resistors dissipate 0.088 mW [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"inline_featured_image":false,"rop_custom_images_group":[],"rop_custom_messages_group":[],"rop_publish_now":"initial","rop_publish_now_accounts":[],"rop_publish_now_history":[],"rop_publish_now_status":"pending","ngg_post_thumbnail":0,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2},"jetpack_post_was_ever_published":false},"categories":[649,4],"tags":[],"class_list":["post-4071","post","type-post","status-publish","format-standard","hentry","category-electronics","category-technology"],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 4.9.8 - aioseo.com -->\n\t<meta name=\"description\" content=\"To calculate the resistance when powering a LED use this: R=(Vpow-Vled)\/I R: is the needed resistance Vpow: is the voltage of our source or power supply (e.g. battery) Vled: voltage of the LED I: the maximum of current that goes through our LED. for a 2V (diode forward voltage) LED we need 20mA =0.02A\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"\u03bc\u03bf.\"\/>\n\t<meta name=\"keywords\" content=\"electronics,technology\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/xylem.aegean.gr\/~modestos\/mo.blog\/leds-resistors\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 4.9.8\" \/>\n\t\t<script type=\"application\/ld+json\" class=\"aioseo-schema\">\n\t\t\t{\"@context\":\"https:\\\/\\\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\\\/\\\/xylem.aegean.gr\\\/~modestos\\\/mo.blog\\\/leds-resistors\\\/#article\",\"name\":\"LEDs & resistors | \\u03bc\\u03bf.\",\"headline\":\"LEDs &#038; 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